The cell Cu(s) | Cu (aq) (0.1 M) || Ag (aq) (0.01 M) | Ag(s) the cell potential E = 0.3095 V For the — Electrochemistry Chemistry Question

Question

The cell Cu(s) | Cu (aq) (0.1 M) || Ag (aq) (0.01 M) | Ag(s) the cell potential E = 0.3095 V For the cell Cu(s) | Cu (aq) (0.01 M) || Ag (aq) (0.001 M) | Ag(s) the cell potential = ______ × 10 V. (Round off the Nearest Integer). 2+ + 1 2+ + –2