AITS & Test SerieshardMCQ SINGLE

See imageAITS & Test Series Chemistry Question

Question

See image

Chemistry diagram for: See image
Answer: B

💡 Solution & Explanation

C=O -802.8 = 4× 416.2 + 2× 493.7 - 2× ΔH - 4× 464.4   C=0 H 798.7 kJ / mol

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