See image — AITS & Test Series Chemistry Question
Question
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Answer: 2.00
💡 Solution & Explanation
(for Q. 37 to 38): Total stereoisomers n 1 2 3 1 2 n 3 = 4 Optically inactive n 1 2 2 = 2 Optical active = 4 – 2 = 2 Number of diastereomeric pair = 5 AITS-FT-VIII (Paper-2)-PCM(Sol.)-JEE(Advanced)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 Mathematics PART – III Section – A
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