At 25ºC, the enthalpy of the following processes are given: H2(g) + O2(g) 2OH(g) Hº = 78 kJ mol–1 H2(g) + 1 O2(g) H2O(g) Hº = 242 kJ mol–1 H2(g) 2H(g) Hº = 436 kJ mol–1 1 O2(g) O(g) Hº = 249 kJ mol–1

Question

At 25ºC, the enthalpy of the following processes are given: H2(g) + O2(g) 2OH(g) Hº = 78 kJ mol–1 H2(g) + 1 O2(g) H2O(g) Hº = 242 kJ mol–1 H2(g) 2H(g) Hº = 436 kJ mol–1 1 O2(g) O(g) Hº = 249 kJ mol–1 What would d be the value of X for the following reaction?_______ (Nearest integer) H2O(g) H(g) +OH(g) Hº = kJ mol–1

Prashant Kotian · Accepted Answer

Correct answer: .. H2O(g)  H(g) +OH(g) Hº = kJ mol–1 2H2O 2H2 + O2 H = +242 × 2 = 484 H2 + O2 2OH H = 78 2H2O H2 + 2OH H = 562 H2 2H H = 436 2H2O 2H + 2OH H = 998 H2O H + OH H = 499

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