See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let   m n m n m m n m 1n 1 mn n 3 m 3 n 3 S 3 3 n 3 m 3                      =   2 n n m m n m 1n 1 m n 3 3 3 n 3 m 3                 =   2 m m n m 1n 1 m n 3 n 3 m 3               Interchanging m and n   2 n n m n 1m 1 n m S 3 m 3 n 3           2 m n m m 1n 1 m 1 mn m 9 2S 16 3 3 3                    9 p S 32 q    q – 3p = 32 – 27 = 5