The vapour pressure of 30% (w/v) aqueous — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

N n Ps Ps Po   density of solution = volume Mass density of solution = 100 ml Mass = 120g weight of glucose = 30 x = 36g weight of H2O = 120 – 36 = 84g mole of glucose = 36/180 = 0.2 mole mole of H2O = 84 = 4.6 mole . 2 . Ps Ps   24 – Ps = 0.0428 Ps Ps = . 24 = 23.015 mm of Hg = 23 mm of Hg