The final partial pressure of gas in the bulb is — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

The pressure of the decomposition products is P_prod = 680 mm Hg. Since $NH_4Cl$(s) ⇌ $NH_3$(g) + $HCl$(g) produces equal moles of $NH_3$ and $HCl$, their partial pressures are equal. Thus, P_NH3 = P_prod / 2 = 680 / 2 = 340 mm Hg.