Correct answer: 00007.65.  h h 1 3 2     3    , this means the electron belongs to n = 4(principal shell) 2 2 n 2 2 z 3 E

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00007.65

💡 Solution & Explanation

 h h 1 3 2     3    , this means the electron belongs to n = 4(principal shell) 2 2 n 2 2 z 3 E

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