See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

A 3B 2C   1 mol of A reacts with 3 mol of B. 5 mol of A will react with 15 mol of B. Given mol of B are 12 which is limiting. Now, 3 mol of B will give 2 mol of C. So, 12 mol of B will give 2 12 ,i.e., 3  8 mol of C.