See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(P) [Ni(CN)4]2– O. S of Ni is +2 2 8 Ni 3d   3d 4s Paramagnetic In presence of ligand 2 8 Ni 3d   3d 4s Diamagnetic 4p 2 dsp (Q) K3[Fe(CN)6] Oxidation state of Fe = +3 3 5 0 Fe 3d 4s   3d 4s Paramagnetic In presence of ligand AITS-FT-X (Paper-2)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6 3d 4s 2 3 d sp 4p Paramagnetic low spin (R) 2 Ni  3d 4s In presence of ligand 3 sp Paramagnetic (S) [Ni(NH3)6]SO4 In presence of ligand 3 2 sp d paramagnetic