See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

    A 2B Product t=0 a a t t, a x a 2x       kt t A ae  kt a x ae     kt x a 1 e   At 1/2 a t t a x 2     a x 2  t B a 2x     kt a 2a 1 e      kt a 2e 1    At t = 0, [B] = a  1/2 t t t , B a 2x    = a – a = 0