Which of the following will have two stereoisomeric forms?<br>(I) [Cr(NO3)3(NH3)3]<br>(II) K3[Fe(C2O — Coordination Compounds Chemistry Question

💡 Solution & Explanation

Step 1: Determine the total stereoisomers for each complex: (I) [Cr(NO3)3(NH3)3] (type [MA3B3]) has 2 geometrical isomers (fac/mer) which are both optically inactive, giving exactly 2 stereoisomers. Step 2: (II) K3[Fe(C2O4)3] (type [M(AA)3]) has 0 geometrical isomers but exists as a pair of optically active d- and l- enantiomers, giving exactly 2 stereoisomers. Step 3: (III) [CoCl2(en)2]^+ and (IV) [CoBrCl(ox)2]^3- both have cis/trans geometrical isomers where the cis isomer is chiral (forming d- and l- forms) and the trans is achiral, resulting in a total of 3 stereoisomers. Thus, only I and II have exactly two stereoisomers (option b).