See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

For nth order reaction   n n 1 n 1 0 1 1 1 k t n 1 a a            …(i) Hence n 1 n 1 n 1/ 2 0 0 1 2 1 k t n 1 a a                         …(ii) AITS-FT-VII-(Paper-1)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7 as 0 a a 2  At 3 / 4 t n 1 n 1 n 3/ 4 0 0 1 4 1 k t n 1 3a a                         …(iii) 0 3/ 4 3a a at t 4  From equations (ii) and (iii) n 1 1/ 2 n 1 3 / 4 t 2 1 t 4 1 3            Hence 1/2 3 / 4 t t is a function of n.