Consider the following cell reaction l s 2 s O H 9 SO Hg Cd l s 4 Hg O H 9 . CdSO The value of Eºcel — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following cell reaction l s 2 s O H 9 SO Hg Cd l s 4 Hg O H 9 . CdSO The value of Eºcell is 4.315 V at 25ºC. If Hº = –825.2 kJ mol–1, the standard entropy change Sº in J K–1 is ______. (Nearest integer) [Given : Faraday constant = 96487 C mol–1] fuEufyf[kr lsy vfHkfØ;k ij fopkj dhft,A l s 2 s O H 9 SO Hg Cd l s 4 Hg O H 9 . CdSO Eºcell dk eku 25ºC ij 4.315 V gSA ;fn Hº = –825.2 kJ mol–1 gS] rks ekud ,UVªksih esa ifjorZu] Sº, J K–1 esa ______gS (fudVre iw.kkZad eas) [fn;k gS : QSjkWMs fLFkjkad = 96487 C mol–1]
💡 Solution & Explanation
For given cell reaction n = 2 and Gº = – nFEºcell, Gº = Hº – TS Then Hº – TSº = –nF Eºcell Hº = 825.2×103 J/mole T = 298 K Eºcell = 4.315 V F = 96485 Cb T H E nF º S º cell ) 2 . ( . 96487 º S = 10 . 10 . 3 10 7482 Sº = 25.1 J/k