An aqueous KCl — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

ution in mol L–1 is…………. (Nearest integer) KCl ds ,d tyh; foy;u dk ?kuRo 1.20 g mL–1 rFkk eksyyrk 3.30 mol kg–1 gSA bl foy;u dh eksyjrk mol L–1 gS…………. (fudVre iw.kkZd esa) Ans. (3) Sol. Molality (m) =           solute M M d 1000 M 3.3 = . M . 1000 M     3960 – 245.85 M = 1000 M 1245.85 M = 3960 M = . 3960 = 3.17  3 M