The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is — JEE Mains Chemistry Past Papers Chemistry Question
Question
The volume (in mL) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is
Answer: .
💡 Solution & Explanation
Phosphinic acid is hypo phosphorous acid (H3PO2). NaOH + H3PO2 NaH2PO2 + H2O For neutrization (N1V1)acid = (N2V2)base 0.1 × 10 = 0.1 × (VmL)NaOH VNaOH = 10 mL
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