See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(NH4)2 Cr2O7 N2 + Cr2O3 + 4H2O -3 +6 O +3 change in oxidation state in Cr = 2 (+6 - 3) = 6 change in oxidation state = 2(-3-0) In 'N" = - 6 Hence nfactor = 6 AITS-CRT-III (Paper-2)-PCM(Sol.)-JEE (Advanced)/2021 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12