In the above problem, if the solution is cooled to -0.200°C, how many gram of ice would separate? — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

At -0.200°C, the depression ΔT_f = 0.200°C. Using the formula: 0.200 = 1.86 * (5 / 60) * (1000 / W_liquid_water) => W_liquid_water = 155 / 0.200 = 775 g. Mass of ice that has separated = 1000 g - 775 g = 225 g.