The ratio of sigma-bond and pi-bond in tetracyano ethylene is : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

Step 1: Write the chemical formula of tetracyanoethylene: C2(CN)4, or (NC)2C=C(CN)2. Step 2: Count the bonds: there are 4 C-C single bonds (4 sigma), 1 C=C double bond (1 sigma, 1 pi), and 4 C#N triple bonds (4 sigma, 8 pi). Total sigma bonds = 4 + 1 + 4 = 9; total pi bonds = 1 + 8 = 9. Step 3: The ratio of sigma to pi bonds is 9 : 9, which simplifies to 1 : 1.