Two positively charged particles m1 and m2 have been accelerated across the same potential difference of 200 keV as shown below. m1 m2 Vacuum Power supply 200 keV [Given mass of m1 = 1 amu and m2 = 4

Question

Two positively charged particles m1 and m2 have been accelerated across the same potential difference of 200 keV as shown below. m1 m2 Vacuum Power supply 200 keV [Given mass of m1 = 1 amu and m2 = 4 amu] The deBroglie wavelength of m1 will be x times of m2. The value of x is _______. (nearest integer)

Prashant Kotian · Accepted Answer

Correct answer: .. d h 2mK.E.  Here KE is same i.e. 200 k eV So d m      2 d m d m m 2 m        d m  = 2  d m  So x = 2.

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