See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the parent chain: The molecule contains a four-carbon chain with a carbonyl (C=O) group at one end forming an amide (C(=O)-NH), so the parent is butanamide (4 carbons including the carbonyl carbon). Step 2 - Number the chain: The carbonyl carbon is C1. Moving along the chain: C1 (carbonyl), C2 (CH2), C3 (CH with Br), C4 (CH3). Step 3 - Identify substituents on the chain: There is a bromine atom on C3, giving the locant '3-bromo'. Step 4 - Identify substituents on nitrogen: The nitrogen of the amide bears a bromine atom directly (N-H-Br means N is substituted with Br), giving 'N-bromo'. Step 5 - Assemble the IUPAC name: Combining the N-bromo substituent, the 3-bromo substituent on the chain, and the parent butanamide gives N,3-dibromobutanamide. Step 6 - Verify: 'di' is used because there are two bromine atoms total (one on N, one on C3); the parent chain has 4 carbons ending in amide. This is fully consistent with the structure drawn. Therefore, the correct answer is N,3-dibromobutanamide.