Correct answer: D. Kp= 2 CO P 1  log Kp= 10  8500 / T log 1 = 10 8500/T T = 850 K

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: D

💡 Solution & Explanation

Kp= 2 CO P 1  log Kp= 10  8500 / T log 1 = 10 8500/T T = 850 K

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