Correct answer: 3.    2 2 1 NO g O g NO g 2    2 o o o r NO NO G G G    = 5.1454 – 1 = 4.1454 Kcal o 10 eq G

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 3

💡 Solution & Explanation

   2 2 1 NO g O g NO g 2    2 o o o r NO NO G G G    = 5.1454 – 1 = 4.1454 Kcal o 10 eq G

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry