Consider the following reaction sequence 3 (i) CO ,NaOH,120ºC, high pressure (ii)H O Compound (x) Co — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following reaction sequence 3 (i) CO ,NaOH,120ºC, high pressure (ii)H O Compound (x) Compound (y) [76.6%C,6.38%H, (Major Product) vapour density 47] Compound (y) develops characteristic colour with neutral FeCl3 solution. Identify the INCORRECT statement from the following for the above sequence. (A) Both compounds x and y will dissolve in NaOH. (B) Compound y will dissolve in NaHCO3 and evolve a gas. (C) Compound x is more acidic than compound y. (D) Both compounds x and y will burn with sooty flame.
💡 Solution & Explanation
(X) 3 (1)CO /NaOH (2)H O YMajor 76.6%C 6.38% H Vapour Density 47 OH COOH Gives colour with FeCl3 Soluble in NaHCO3 Soluble in NaOH Y = Salicylic acid Compound (X) is OH (1) CO2 NaOH (2) H3O+ OH COOH Kolbe Schmitt reaction