For the reaction given below at 25°C For More Join: @IITJEE_Advanced Rankers Academy JEE A2 ⇌ 2A Find lnKp Given (∆G°f)A = - 50.384 KJ/mol Given = - 100 KJ/mol ∆𝐺𝑓 𝑜 ( )𝐴2 A) 0.43 B) 0.23 C) 0

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Question

For the reaction given below at 25°C For More Join: @IITJEE_Advanced Rankers Academy JEE ​ ​ A2 ⇌ 2A Find lnKp Given (∆G°f)A = - 50.384 KJ/mol Given = - 100 KJ/mol ∆𝐺𝑓 𝑜 ( )𝐴2

A) 0.43
B) 0.23
C) 0.31
D) 0.53

Prashant Kotian · Accepted Answer

Correct answer: C

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