The calculated spin-only magnetic moments of K3[Fe(OH)6] and K4(Fe(OH)6) respectively are : (A) 4.90 — JEE Mains Chemistry Past Papers Chemistry Question
Question
The calculated spin-only magnetic moments of K3[Fe(OH)6] and K4(Fe(OH)6) respectively are : (A) 4.90 and 5.92 B.M. (B) 4.90 and 4.90 B.M. (C) 3.87 and 4.90 B.M. (D) 5.92 and 4.90 B.M.
Answer: D
💡 Solution & Explanation
For K3[Fe(OH)6] Oxidation number of Fe = +3 Fe(+3) = 3d5 Configuration in W.F.L. ,1 ,1 g 2t ,1 g e 5 unpaired electrons = ) 5 ( = 5.92 B.M. For K4[Fe(OH)6] Oxidation number of Fe = +2 Fe(+2) = 3e6(W.I.L.) Configuration will be ,1 g 2t ,1 g e 4 unpaired electrons = ) 4 ( = 4.9 B.M. Ans. 4
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