See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. 1 2 1 1 2 1 ms 2 , ms 3 , 2 , 1       u u kg m kg m Initial momentum 2 2 2 2 1 1 ) ( ) ( u m u m   16 9   = 5 kg ms–1 If combined velocity is v, 5 ) ( 2 1   v m m , 1 ms 3 5   v Heat liberated = loss in kinetic energy J v m m u m u m 3 13 ) ( 2 1 2 1 2 1 2 2 1 2 2 2 2 1 1      =4.33J