See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the resistance be R, Therefore, rms 110 I A R  With L, rms 2 2 2 220 110 I R R L     2 5 4 R 10 3   2 With C, rms 2 2 220 110 I R 1 R C           C = 5F