[SEE DIAGRAM] P(aq.) --(Zn + dil. HCl)--> Qβ Qβ --(FeCl3)--> Rβ + T (coloured ion) Qβ --(MnO4^- / H^ β Qualitative and Quantitative Analysis Chemistry Question
Question
[SEE DIAGRAM] P(aq.) --(Zn + dil. HCl)--> Qβ Qβ --(FeCl3)--> Rβ + T (coloured ion) Qβ --(MnO4^- / H^+)--> Rβ (white turbidity) + Mn2+(aq.) P(aq.) --(Ξ)--> Rβ + S
![Chemistry diagram for: [SEE DIAGRAM] P(aq.) --(Zn + dil. HCl)--> Qβ Qβ --(FeCl3)--> Rβ + T (coloured ion) Qβ --(MnO4^- / H^+)--> Rβ (white turb](/_next/image?url=https%3A%2F%2Furywdhpqdpvmqzlenttu.supabase.co%2Fstorage%2Fv1%2Fobject%2Fpublic%2Fquestion-images%2Fvkj%2Fch10_l3_Q002.png&w=1920&q=75)
π‘ Solution & Explanation
Step 1: When NaOH is added to the mixture containing Al3+, Zn2+, and Cu2+, all of them initially form hydroxide precipitates. Step 2: Since Al(OH)3 and Zn(OH)2 are amphoteric, they dissolve in excess NaOH to form soluble aluminate ([Al(OH)4]-) and zincate ([Zn(OH)4]2-) complexes. Step 3: In contrast, Cu(OH)2 is a basic hydroxide and remains insoluble as a characteristic blue precipitate, allowing both the identification and separation of Cu2+ in one step, matching option (c).