See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

[Range : 2.90 – 3.00] Sol.        3 2 2 2 2Pb NO 2PbO 4NO O   3 2 2 332 gm Pb NO gives 2 224 gm Pb      3 2 224 x gm Pb NO gives x gm 332    3 2 2 1 NaNO NaNO O 2    For More Material Join: @JEEAdvanced_2024 AITS-FT-IX (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11 3 2 85 gm NaNO gives 69 gm NaNO      3 69