Following Kjeldahl's method, 1g of organic compound released ammonia, that neutralised 10 mL of 2M H — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

H2SO4 + 2NH3 (NH4)2 SO4 Millimole of H2SO4 10 × 2 So Millimole of NH3 = 20 × 2 = 40 Organic  NH3 Compound 40 Millimole Mole of N = 40 wt. of N = 40 1000  % composition of N in organic compound 40 14 1000 1     = 56%