A diatomic ideal gas initially at 273 K is given 100 cal heat due to which system did 210 J work. Molar heat capacity of the gas for the process is (1 cal = 4.2 J)

Question

Prashant Kotian · Accepted Answer

Correct answer: D. Heat added q = 100 cal = 420 J. Work done by system is 210 J, so w = -210 J. Change in internal energy dU = q + w = 420 - 210 = 210 J. For a diatomic ideal gas, = 2.5 R. dU = n * * dT = n * 2.5 R * dT = 210 J => n * dT = 84 / R. Molar heat capacity C = q / (n * dT) = 420 / (84 / R) = 5R.

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