See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

HBr   CH2 C H3 Br  A o1 alkyl bromide C H2 CH2 Thus, (A) is correct. B is formed by SN reaction. B is C C CH2 CH3 B C C CH2 H H CH3 Lindlar catalyst  C cis C C CH2 H H OH OH CH3 4 MnO / OH    D For More Material Join: @JEEAdvanced_2024 AITS-FT-X-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9 Lindlar catalyst converts alkyne into cis-isomer. Thus, (C) is correct. 4 dil. MnO / OH   and two (- OH) on alkene. Thus, (B) is correct. By syn-addtion. Thus, (C) changes into cis isomer. Thus, (D) is incorrect.