Question No. 1 to 3 (3 questions) (i) P + C(carbon) + Cl2 Q + CO (ii) Q + H2O R + HCl (iii) BN + H2O R + NH3 (iv) Q + LiAlH4 S + LiCl + AlCl3 (v) S + H2O R + H2 (vi) S + NaH T (P, Q, R, S and T do not

Question

Question No. 1 to 3 (3 questions)
(i) P + C(carbon) + Cl2 $\rightarrow$ Q + CO $\uparrow$
(ii) Q + H2O $\rightarrow$ R + HCl
(iii) BN + H2O $\rightarrow$ R + NH3 $\uparrow$
(iv) Q + LiAlH4 $\rightarrow$ S + LiCl + AlCl3
(v) S + H2O $\rightarrow$ R + H2 $\uparrow$
(vi) S + NaH $\rightarrow$ T
(P, Q, R, S and T do not represent their chemical symbols)

Prashant Kotian · Accepted Answer

Correct answer: C. Step 1: Note that under anhydrous conditions, aluminium chloride exists as a covalent dimer, Al2Cl6. Step 2: Upon dissolving in water, the hydration of the aluminum center causes ionic dissociation. Step 3: According to the specific textbook solution key, this dissociation is represented by the formation of complex ions [AlCl2(H2O)4]+ and [AlCl4(H2O)2]-, matching option (c).

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