There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S

Question

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, 
Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 
2.5 respectively and rest two species S and T are heteronuclear diatomic species
and have bond order 3 and 2 respectively. All homonuclear diatomic species are 
paramagnetic and all heteronuclear diatomic species are diamagnetic in nature. 
P, R, S and T are monovalent positive ion and Q is monovalent negative ion :

Prashant Kotian · Accepted Answer

Correct answer: C. Step 1: Understand that the potential energy of a bonding system reaches a minimum at the optimum internuclear distance (bond length), balancing attractions and repulsions. Step 2: If the internuclear distance is decreased below this optimum distance, the nuclei and core electron clouds are forced too close together. Step 3: This leads to a massive, steep increase in potential energy due to the sharp increase in electrostatic repulsions between the positively charged nuclei and between the negatively charged electron clouds.

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