Correct answer: 00099.93. Vol. occupied by 1 mole of H2O (g) at 373 k = nRT / P = 1 0.0821 373

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 00099.93

💡 Solution & Explanation

Vol. occupied by 1 mole of H2O (g) at 373 k = nRT / P = 1 0.0821 373

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET