When the concentration of reactant in the reaction: A -> B is increased by 8 times, the rate increas — Chemical Kinetics Chemistry Question
Question
When the concentration of reactant in the reaction: A -> B is increased by 8 times, the rate increases only by 2 times. The order of reaction is
Answer: B
💡 Solution & Explanation
rate is ∝ [A]^n => rate2 / rate1 = ([A]2 / [A]1)^n => 2 = 8^n => 2^1 = (2^3)^n => 3n = 1 => n = 1/3.
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