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Name: JEE Advanced Chemistry
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Question

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Prashant Kotian · Accepted Answer

Correct answer: 00000.50.  x 2 x A sin            x d 2 2 x Acos dx              2 2 x 2 d 2 2 x A sin dx                  So, n = 2, m = -4, p = 2, q = 2   2 2 x x 2 2 d 4 dx    

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