See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

At x = 1m, K.E. is maximum  vmax  a = 0  F kx = 0; F = k(1) At that point, W.E. theorem 2 2 1 1 F(1) k(1) mv 4 2 2    k F 4 2   F F 4 2   F = 8N