The ratio of circumference of third and second orbits of He^+ ion is — Atomic Structure Chemistry Question
Question
The ratio of circumference of third and second orbits of He^+ ion is
Answer: C
💡 Solution & Explanation
Circumference C = 2*π*r ∝ n^2. C_3/C_2 = 3^2/2^2 = 9:4.
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