At 300 K, the vapour pressure of a — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Ptotal = Pºhexane . Xhexane + Pºheptane . Xheptane 550 = [Pºhexane] × 4 1 + [Pºheptane] × 4 ….(i) After mixing 1 mole n-heptane 560 = [Pºhexane] × 5 1 + [Pºheptane] × 5 ….(ii) On solving eq. (i) and (ii) Pºheptane = 600 mm of Hg | JEE MAIN-2020 | DATE : 04-09-2020 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10