The shortest wavelength of H atom in the Lyman series is 1. The longest wavelength in the Balmer ser — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

For hydrogen atom : For Lyman series n1 = 1 & n2 =  H  = RH      1 1 So,  = H R For He+ ion | JEE MAIN-2020 | DATE : 04-09-2020 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 9 Balmer series n1 = 2 & n2 = 3  He = RH × Z2     9 4  He = RH × 4 × 5  He = 5 RH =        9    He = 9 