JEE Mains Chemistry Past PapershardMCQ SINGLE

In figure, a straight line is given for Freundrich Adsorption (y = 3x + 2.505). The value of n 1 andJEE Mains Chemistry Past Papers Chemistry Question

Question

In figure, a straight line is given for Freundrich Adsorption (y = 3x + 2.505). The value of n 1 and log K are respectively. m x log Y log P X log K n l (A) 3 and 2.505 (B) 3 and 0.7033 (C) 0.3 and log 2.505 (D) 0.3 and 0.7033

Answer: A

💡 Solution & Explanation

For straight line y = mx + c log       m x = m[log P] + C From freundlich adsorption log       m x = n 1 logP + log K so n 1 = 3 and log K = 2.505

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