Flask with greater number of collisions with the walls per unit area per unit time — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

The collision rate with the walls is ∝ N* × u_avg. For a given mass and volume, N* ∝ 1/M. Average speed u_avg ∝ √(T/M). Thus, collision rate ∝ √(T) / M^1.5. Evaluating this ratio: Flask A ($H_2$, T=300): √300 / 2^1.5 ≈ 6.12. Flask B ($CH_4$, T=600): √600 / 16^1.5 = 24.5 / 64 ≈ 0.38. Flask C ($O_2$, T=900): √900 / 32^1.5 = 30 / 181 ≈ 0.16. Clearly, Flask A has the highest wall collision frequency.