x mg of pure HCl was used to make an aqueous — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

ution. 25.0 mL of 0.1M Ba(OH)2 solution is used when the HCl solution was titrated against it. The numerical value of x is ______ × 10 –1. (Nearest integer) Given : Molar mass of HCl and Ba(OH)2 are 36.5 and 171.0 g mol –1 respectively. Ans. (1825) Sol. Ba(OH)2(aq) + 2HCl(aq)  BaCl2(aq) + 2H2O() 2.5 mmole 5mmole wt of HCl = 5 × 36.5 (milligram) = 182.5 (milligram) Hence x = 1825.