See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

6 5 2 2 6 5 3 C H NH H O C H NH OH 1 0 0 1           (Dissociation occurs in presence of NaOH and thus dissociation of C6H5NH2 will suppress) 8 6 5 3 b 6 5 2 [C H NH ][OH ] 10 x [OH ] K [C H NH ] [0.24]        Kb for C6H5NH2 = 14 w 5 a 6 5 3 K 10 K for C H NH