See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(for the Q. No. 31 and 32) O 2 NaNO HCl  O N O O N O H 3 H O  O O P O O   3 1 OH 2 H O  P OH C O OH Q Molar mass of P = 112 For More Material Join: @JEEAdvanced_2024 AITS-FT-VIII (Paper-2)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 % of Carbon in 72 P 100 112   = 64.285 OH CO2H Q Molar mass of Q = 130 130