Correct answer: 00007.00. 2 Cu e Cu     2 2 2 I I e   2 2 3 4 6 2 2 S O S O e     2+ 2 2 2 3 Meq.of Cu =Meq.of liberated I .

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00007.00

💡 Solution & Explanation

2 Cu e Cu     2 2 2 I I e   2 2 3 4 6 2 2 S O S O e     2+ 2 2 2 3 Meq.of Cu =Meq.of liberated I .

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