See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

hc hc eEd     On solving we get 0 1 1 eEd hc     24.   2 cos & P F tomirror directed toward it c     25. v 2m Before collision 2 4 .E 4 pi mv mk m units    1 2 2 1 2 p y p y m m units      AITS-CRT-III-PCM (Sol.)-JEE(Main)/18 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6 Energy of dissociation =         2 2 1 2 2 2 2 1 2 2 4 2 2 1 2 2 3 1 1 3 y p p ev m m m m m ev m m ev ev                            