The general formula of polythionate ion is Sn+2O6^2-. if average oxidation state of 'S' atom in any polythionate ion is equal to bond order of 'S—O' bond. Then calculate the value of 'n' for the corre

Question

The general formula of polythionate ion is Sn+2O6^2-. if average oxidation state of 'S' atom in any polythionate ion is equal to bond order of 'S—O' bond. Then calculate the value of 'n' for the corresponding polythionate ion.

Prashant Kotian · Accepted Answer

Correct answer: 4 / BOND ORDER OF 'S—O' BOND IS 1.66 (5/3). AVERAGE OXIDATION STATE OF 'S' ATOM IS: 10 / (2+N) = 5/3 $\RIGHTARROW$ 2+N=6 $\RIGHTARROW$ N=4. Step 1: Heating borax on a platinum wire loop forms a transparent, glassy bead of sodium metaborate (NaBO2) and boric anhydride (B2O3). Step 2: When this hot bead is touched to a transition metal salt and heated again, the metal oxide reacts with B2O3 to form colored transition metal metaborates. Step 3: Because the characteristic colored beads are formed by these specific transition metal metaborates, option (c) is the correct choice.

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